## Tuesday, March 15, 2011

### Jennily's Great Big Book Of Integers

Chapter 1
Integers
- Number lines
- Integer chips
- Zero pairs

= -1

= +1

These are negative and positive numbers.

= Zero Pairs

This is a rhyme that can help you remember zero pairs. " When subtracting something that isn't there use a zero pair".

Integers in grade 7
have 4 owe 4
(+4) + ( - 4) = 0

Brackets in grade 7 are training wheels.
Standard Form
+4-4
4-4 <--- pure standard form
6-4 = 2

The ones that are in the box are the ones that are removed so it means there are +2 piece of chips left.

Chapter 2 - "Multiplying Integers"
(+2) x (+3) =
or
2 groups of (+3)

(+2) x (-3)= or 2 groups of (-3)

(-2) x (+3)= -6 <----- remove 2 groups of (+3) for this you would have to use zero pairs.

(-2)x(-3) = +6 <---- Remove 2 groups of (-3)

Sign Rule ( negative signs)
Even= When you have an even number of NEGATIVE factors the product is POSITIVE.
Odd = When you have an odd number of NEGATIVE factors the product is NEGATIVE.

Chapter 3 " Dividing Integers"
Division
2 types of division
6/3= 2
How many groups of (+3) are in 6?
Partative division or making parts.
<----------------------->
0 -------> ---------> 6

6/3 = 2
Share 6 with 3 groups
+1 +1 +1
+1 +1 +1
Quotative division or sharing your total with groups.
(-6)/(-3)=2
How many groups of (-3) are in -6?
Only Partative will work for this.

If you have no negative or an even number of negative signs in a division question the quotient is positive.

When you have and odd number of (-) signs in a division question the quotient is negative.

Chapter 4 - Order of operations with integers

(+6) x (-2) + (-6) ÷ (+2)= ?

1) You would use the multiplication and division first
2)Then p
ut the square brackets around (+6) x (-2) ex. [(+6) x (-2)]
3)After p
ut square brackets around (-6) ÷ (+2) ex. [(-6) ÷ (+2)]
4)Finally solve (-12)+(-3) = + 15