Integers

The ones that are in the box are the ones that are removed so it means there are +2 piece of chips left.

- Number lines

- Integer chips

- Zero pairs

= -1

= +1

These are negative and positive numbers.

= Zero Pairs

This is a rhyme that can help you remember zero pairs. " When subtracting something that isn't there use a zero pair".

Integers in grade 7

have 4 owe 4

(+4) + ( - 4) = 0

Brackets in grade 7 are training wheels.

Standard Form

+4-4

4-4 <--- pure standard form

6-4 = 2

Chapter 2 - "Multiplying Integers"

(+2) x (+3) =

or

2 groups of (+3)

(+2) x (-3)= or 2 groups of (-3)

(-2) x (+3)= -6 <----- remove 2 groups of (+3) for this you would have to use zero pairs.

(-2)x(-3) = +6 <---- Remove 2 groups of (-3)

Sign Rule ( negative signs)

Even= When you have an even number of NEGATIVE factors the product is POSITIVE.

Odd = When you have an odd number of NEGATIVE factors the product is NEGATIVE.

Chapter 3 " Dividing Integers"

Division

2 types of division

6/3= 2

How many groups of (+3) are in 6?

Partative division or making parts.

<----------------------->

0 -------> ---------> 6

6/3 = 2

Share 6 with 3 groups

+1 +1 +1

+1 +1 +1

Quotative division or sharing your total with groups.

(-6)/(-3)=2

How many groups of (-3) are in -6?

Only Partative will work for this.

If you have no negative or an even number of negative signs in a division question the quotient is positive.

When you have and odd number of (-) signs in a division question the quotient is negative.

Chapter 4 - Order of operations with integers

**(+6) x (-2) + (-6) ÷ (+2)= ?**

1) You would use the multiplication and division first

2)Then put the square brackets around (+6) x (-2) ex. [(+6) x (-2)]

3)After p

1) You would use the multiplication and division first

2)Then put the square brackets around (+6) x (-2) ex. [(+6) x (-2)]

3)After p

**ut square brackets around (-6) ÷ (+2) ex. [(-6) ÷ (+2)]**

4)Finally solve (-12)+(-3) = + 15

4)Finally solve (-12)+(-3) = + 15

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