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Showing posts with label "volume problems". Show all posts
Showing posts with label "volume problems". Show all posts
Thursday, March 17, 2011
Breanna's Volume Post
Labels:
"cylinder volume",
"volume problems",
Breanna873,
Surface Area,
Volume
Tuesday, March 1, 2011
Surface Area and Volume
Here is a question from 7.3 in the text book :

r=d/2 v=πr² x h
r=8/2 v=(3.14x4x4) x 10m
r=4m v=50.24m² x 10m
v= 502.4m³
Now, since it is only half of a cylinder, I have to divide by 2
502.4m³/ 2= 251.2m³
The area of the semi-circular trough is 251.2cm³
Here is a question from 7.4 in the textbook :

____
³ )8000 = 20 d/2=r v= πr² x h
20/2=r v= (3.14x10x10) x 20
10cm=r v= 314cm²x 20cm
v= 6280cm³
The volume of the vase is 6280cm³

r=d/2 v=πr² x h
r=8/2 v=(3.14x4x4) x 10m
r=4m v=50.24m² x 10m
v= 502.4m³
Now, since it is only half of a cylinder, I have to divide by 2
502.4m³/ 2= 251.2m³
The area of the semi-circular trough is 251.2cm³
Here is a question from 7.4 in the textbook :

____
³ )8000 = 20 d/2=r v= πr² x h
20/2=r v= (3.14x10x10) x 20
10cm=r v= 314cm²x 20cm
v= 6280cm³
The volume of the vase is 6280cm³
Labels:
"cylinder volume",
"volume problems",
AlecM873,
Surface Area,
Volume
Cylinder Problems and Volume Problems
Wednesday, February 23, 2011
Textbook Volume Post
Pg.261
questions:18,19

18)Suki has 30 small linking cubes.
a)She wants to use 18 of them to make a large cube,Is this possible?
Why or not?
b)what number of linking cubes would she use to construct the largest cube she can possibly make?
a)There's no whole number that can be cubed to equal 18,so NO.
b)Suki would have to have 27 more cubes to make 3x3x3 cubed.

19)Melissa has three glass vases,She wants to use one as a decorative fish tank for Harvey the guppy.Which will give Harvey the most water to swim in?
The volume of the cube is 343 cm3
The volume of the rectangular prism is is 360 cm3
The volume of the triangular prism is 367.5 cm3
The guppy will have more water to swim in the triangular prism!
Cylinder and Volume Question's

I solve the problem like this
a) V=pi.r.r.h
V=(3.14x3.5x3.5)x23
V=78.5x25
V=1806.5cm^3
b)V=pi.r.r.h
V=(3.14x14x14)x12
V=61.44x12
V=7385.28cm^3
c) V=pi.r.r.h
V=(3.14x0.5x0.5)x1.5
V=12.75x1.5
V=19.125cm^3

R=D/2
D=0.8
o.8/2=R
R=0.4cm^3
V=pi.r.r.h
V=(3.14xo.4xo.4)x10
V=o.5024x10
V=5.024m^3
Chapter 2
(+2) x (+3)=+6
(+2) x (-3)= -6
(-2) x (+3)=(+6)
(-2) x (-3)=+6
questions:18,19

18)Suki has 30 small linking cubes.
a)She wants to use 18 of them to make a large cube,Is this possible?
Why or not?
b)what number of linking cubes would she use to construct the largest cube she can possibly make?
a)There's no whole number that can be cubed to equal 18,so NO.
b)Suki would have to have 27 more cubes to make 3x3x3 cubed.

19)Melissa has three glass vases,She wants to use one as a decorative fish tank for Harvey the guppy.Which will give Harvey the most water to swim in?
The volume of the cube is 343 cm3
The volume of the rectangular prism is is 360 cm3
The volume of the triangular prism is 367.5 cm3
The guppy will have more water to swim in the triangular prism!
Cylinder and Volume Question's

I solve the problem like this
a) V=pi.r.r.h
V=(3.14x3.5x3.5)x23
V=78.5x25
V=1806.5cm^3
b)V=pi.r.r.h
V=(3.14x14x14)x12
V=61.44x12
V=7385.28cm^3
c) V=pi.r.r.h
V=(3.14x0.5x0.5)x1.5
V=12.75x1.5
V=19.125cm^3

R=D/2
D=0.8
o.8/2=R
R=0.4cm^3
V=pi.r.r.h
V=(3.14xo.4xo.4)x10
V=o.5024x10
V=5.024m^3
Chapter 2
(+2) x (+3)=+6
(+2) x (-3)= -6
(-2) x (+3)=(+6)
(-2) x (-3)=+6
Thursday, February 17, 2011
Colleen's Volume Scribe
Textbook. Page: 258-259 #4,5,6.
4) Determine the volume of each triangular prism.



5) What is the volume of each rectangular prism?


6)Determine the volume of each cube.



Cylinder Volume and Volume Problems

area of base x height
r= d/2r
r= 45/2=22.5
r=22.5cm
a= pi.r^2
a= 3.14 x 22.5 x 22.5
a= 1589.625cm^2
v= 1589.625cm^2 x 90cm
v= 143066.25

One crate will be enough. the volume of the crate is 63m^3 and the volume of the boxes is 50m^3
4) Determine the volume of each triangular prism.



5) What is the volume of each rectangular prism?


6)Determine the volume of each cube.



Cylinder Volume and Volume Problems

area of base x height
r= d/2r
r= 45/2=22.5
r=22.5cm
a= pi.r^2
a= 3.14 x 22.5 x 22.5
a= 1589.625cm^2
v= 1589.625cm^2 x 90cm
v= 143066.25

One crate will be enough. the volume of the crate is 63m^3 and the volume of the boxes is 50m^3
Labels:
"cylinder volume",
"volume problems",
Colleen873,
scribepost,
Volume
Math Textbook Pg 250-253 #2,5,8,10
Jennily's Volume Post # 2,5,8,10


No it doesn't matter.







For example look at these two rectangular prism.
V= area of base x height
V= 50cm x 15cm
V= 750cm
V= area of base x height
V= 75cm x 10cm
V=750cm
You see they are both the same.

LxWxH
4cm x 3cm = 12cm
12cm² x 5cm = 60cm³
LxWxH
5cm x 3cm = 15cm
15cm² x 4 = 60cm³

LxWxH
20cm x 6cm = 120cm
120cm² x 8cm = 960cm
LxWxH
8cm x 6cm = 48cm
48cm² x 20 = 960cm³

So, mainly 1cm cube would look like this:
So if you were to make a base of fifteen cm cube it would look something like this:

The top of this layer should be 15cm² so we would use that as our base.

Since the prism is made up of 5 layers of the 15 cm cubes then i will be using that as my height.
V= area of base x height
V= 15cm² x 5cm
V=75cm³
V= 15cm² x 5cm
V=75cm³

Even if the wording is different it's basically just asking for the volume.
V= area of base x height
V= 1250cm² x 100cm
V= 125 000cm³
Cylinder Volume and Volume Problems
7.3
A)
V= π x r x r x h
V= (3.14 x 5 x 5) x 23
78.5cm ^2 x 23
V= 1805.5cm^3
B)
V= π x r x r x h
V= (3.14 x 14 x 14) x 12
615.44cm^2 x 12
V= 7385.28cm^3
C)
V= π x r x r x h
V= (3.14 x 0.5 x 0.5) x 1.5
0.785m^2 x 1.5
V= 1.1775m^3
7.4

A) Yes, He has enough small prism. If he uses 4 for the base and 4 for the height he will have enough.
B)
b x h / 2 x h
5.6 x 6.8 / 2 = 19.04m ^2
19.04m^2 x 1.18 = 22.4672m^ 3
V= 1250cm² x 100cm
V= 125 000cm³
Cylinder Volume and Volume Problems
7.3
A)
V= π x r x r x h
V= (3.14 x 5 x 5) x 23
78.5cm ^2 x 23
V= 1805.5cm^3
B)
V= π x r x r x h
V= (3.14 x 14 x 14) x 12
615.44cm^2 x 12
V= 7385.28cm^3
C)
V= π x r x r x h
V= (3.14 x 0.5 x 0.5) x 1.5
0.785m^2 x 1.5
V= 1.1775m^3
7.4

A) Yes, He has enough small prism. If he uses 4 for the base and 4 for the height he will have enough.
B)
b x h / 2 x h
5.6 x 6.8 / 2 = 19.04m ^2
19.04m^2 x 1.18 = 22.4672m^ 3
Labels:
"cylinder volume",
"volume problems",
JennilyL873,
scribepost,
Volume
Wednesday, February 16, 2011
Angelique's Homework Book Volume Scribe
From the homework book, I did questions 4, 6, and 8 on pages 80-81

For number 6, I solved the problems two different ways.


Here is a link that you might want to look at for some help on volume.

For number 6, I solved the problems two different ways.


Here is a link that you might want to look at for some help on volume.
Here is a video that helps you learn more about volume.
Labels:
"cylinder volume",
"volume problems",
Angelique873,
scribepost,
Volume
Tuesday, February 15, 2011
Karl's Homework Book Post
Homework Book
Even #'s, Pages 78-79.
4.a)

b)

c)

Answers
4.a)
V=area of base x height
V=100cm² x 4cm
V=400cm³
b)
V=area of base x height
V=113cm² x 3cm
V=339cm³
c)
V=area of base x height
V=80cm² x 12cm
V=960cm³
6) Which rectangular prism has the larger volume? Show your thinking.
a)

b)

Answers:
a)
V=area of base x height
V=40cm² x 5cm
V=200cm³
V=area of base x height
V=20cm² x 10cm
V=200cm³
Both of them have a volume 200cm³
b)
V=area of base x height
V=10.5m² x 1m
V=10.5m³
V=area of base x height
V=3m² x 3.5m
V=10.5m³
8)
Even #'s, Pages 78-79.
4.a)

b)

c)

Answers
4.a)
V=area of base x height
V=100cm² x 4cm
V=400cm³
b)
V=area of base x height
V=113cm² x 3cm
V=339cm³
c)
V=area of base x height
V=80cm² x 12cm
V=960cm³
6) Which rectangular prism has the larger volume? Show your thinking.
a)

b)

Answers:
a)
V=area of base x height
V=40cm² x 5cm
V=200cm³
V=area of base x height
V=20cm² x 10cm
V=200cm³
Both of them have a volume 200cm³
b)
V=area of base x height
V=10.5m² x 1m
V=10.5m³
V=area of base x height
V=3m² x 3.5m
V=10.5m³
8)
Nikki and Taylor have to fill the pool this summer. The area of the pool bottom is 27m². The height that the water needs to be is 0.9m. How much water do they need to put in the pool?
Answers:
V=area of base x height
V=27m² x 0.9m
V=24.3m³
They need to put 24.3m³ of water in the pool.
Cylinder Problems and Volume Problems

a)V=pi.r.r.h
V=(3x2x2)x10
V=120m^3
b)V=pr.r.r.h
V=(3.14x2x2)x10.5
V=131.88m^3

Answers:
V=area of base x height
V=27m² x 0.9m
V=24.3m³
They need to put 24.3m³ of water in the pool.
Cylinder Problems and Volume Problems

a)V=pi.r.r.h
V=(3x2x2)x10
V=120m^3
b)V=pr.r.r.h
V=(3.14x2x2)x10.5
V=131.88m^3

d/2 = r
8 / 2 = r
4cm = r
V = pi.r.r.h
V = (3.14x4x4)x40
V= 2009.6cm^3
8 / 2 = r
4cm = r
V = pi.r.r.h
V = (3.14x4x4)x40
V= 2009.6cm^3
Labels:
"cylinder volume",
"volume problems",
Karl873,
Volume
Jasmin's Volume Scribe Post
Show you know-
Pg. 248
Question:

My answer:

Pg. 249
Question:
My answer:

My textbook answers- Page. 250-253 (#1-18)
** I did questions 1,4 and 7
Question #1-

My answer for #1-

Question #4-

My answer for #4-

Question #7-

My answer for #7-

Here is a link on how to calculate volume.
Here is a video.
Cylinder Volume and Volume Problems
7.3
My answer-

If Martha wants to buy more popcorn for her money,
she should get the popcorn container named "Popcorn Lover's."
7.4
My answer-
An assumption I made was that 1/4 of the cheese was cut.
Here is my video on how I solved the math problems-
Pg. 248
Question:

My answer:

Pg. 249
Question:

My answer:
My textbook answers- Page. 250-253 (#1-18)
** I did questions 1,4 and 7
Question #1-

My answer for #1-
Question #4-

My answer for #4-
Question #7-

My answer for #7-
Here is a link on how to calculate volume.
Here is a video.
Cylinder Volume and Volume Problems
7.3
My answer-

If Martha wants to buy more popcorn for her money,
she should get the popcorn container named "Popcorn Lover's."
7.4
My answer-
An assumption I made was that 1/4 of the cheese was cut.
Here is my video on how I solved the math problems-
Labels:
"cylinder volume",
"volume problems",
Jasmin873,
scribepost
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