Joshua's Great Big Book Of Integers

Chapter 1

Grade 7 Integer Review

Integers can be represented with number lines or integer chips.

Negative - Blue
Positive - Red

Zero Pairs - a pair of negative and positive numbers whose sum is 0.

ex. (-8) + (+8) = 0.

This song will help you remember when to use a zero pair:
When subtracting something that isnt there, use a zero pair.

This is how we did integers in Grade 7.

Here are some questions we did.

Chapter 2

Multiplying Integers

Here we learned how to multiply integers. Here are some questions we did.

For questions needing a zero pair you can find out how many zero pairs you need by multiplying the two factors in the question without their negative or positive signs.

ex. (-2) x (+3) - 2 x 3 = 6

6 zero pairs

Chapter 3

Dividing Integers

Partative Division or groups of

If you know the number of groups, but you dont know the number in each group then that is partative division.

Quotative Division

If you know the number that is in each group, but you dont know the number of groups then that is quotative division.

You could also find the answer to a division question using multiplicated-inverse

In a division question with an even amount or no (-) signs the quotient will be positive.
In a divison question with an odd amount of negative signs the quotient will be negative.

Chapter 4

Order of Operations with Integers

(+5) x (-3) + (-6) / (+3) =

To answer this question you will need to folow the rules of B.E.D.M.A.S. Brackets, Exponents, Division, Multiplication, Addition, Subtraction.

First add square brackets around the expressions with a x or / to help remind you to answer them first. The square brackets means that you should answer the question in them before doing anything else.

Jomer's Great Big Book Of Integers

Chapter 1 Grade 7 Integer Review

Questions:
-3 - (-7)= +4
-3 -7= -10
3 -7= 4
3 +7= 10
-3 +7= 4

Chapter 2 Multiplying Integers

(+2) x (+3)=

(+2) x (-3)=

(-2) x (+3)=

(-2) x (-3)=

Sign Rule (Negative signs)
Even: When you have an even number of negative factors the product is positive.
Odd: When you have an odd number of negative factors the product is negative .

Chapter 3 Dividing Integers

Partitive Division is how many groups of a number are in a given value.

Quotative Division is sharing a certain number between a given value.

Sign Rule

In a division question with an even amount or no (-) signs the quotient will be positive.
In a division question with an odd number of (-) signs the quotient will be negative.

Order of Operations with Integers

[(+5)x(-3)]+(-6)/(+3)=-7

(-15)+(-6)/(+3)=-7

(-21)/(+3)=-7

Brandon's Great Big Book of Integers

Chapter 1

Grade 7 Integer Review

Questions for class

-8 - (-4) = -4

-10 + 8 = -2

8 - 7 + 2 = 3

17 - (-3) = 14

- 5 - (-7) = 2

- 2 - 5 = -7

3 - 7 = -4

5 + 5 = + 10


-5 + 6 = - 1

Chapter 2

Multiplying Integers
(+4)x(+2) = 8

Make 4 groups of positive 2


Make 4 groups of negative 2

(+4)x(-2) = -8

(-4)x(+2) = -8
Remove 4 groups from positive 2


(-4)x(-2)= 8

Remove 4 groups of negative 2

Chapter 2

Dividing Integers

Even = When you have a even number of negative factors your product is positive.

Odd = When you have a odd number of negative factors your product is negative.

Partitive Division - when you use groups to find your quotient.

6 ÷ 2 = 3


(-6) ÷ (-2) = 3

Quotative Division - Sharing numbers in groups

(-6) ÷ 2 = - 3

Chapter 4

Order of Operations

(+6) x (-2) + (-6) ÷ (+2)= ?

1) Always do multiplication and division first
2)Put square brackets around (+6) x (-2) ex. [(+6) x (-2)]
3)Put square brackets around (-6) ÷ (+2) ex. [(-6) ÷ (+2)]
4) Solve (-12)+(-3) = + 15

Breanna's Great Big Book of Integers

Chapter 1:

Adding and Subtracting Integers

-6-(-4)= (-2)

-10+6= (-4)

6-7+2= 1

14- (-3)= 17

-3-(-7)= 4

-3-7= (-10)

Chapter 2:

Multiplying Intergers

Examples:

(+3)x(+2)= 3 groups of 2

repeated addition

2+2+2= +6

two groups of +3

(2)x (+3)=

Questions

(+2)x(+3)= +6

2 groups of (+3)

(-2)x(+3)= -6

Sign Rules

Even- When you have an even number of negative factors the product is positive.

Odd- When you have an odd number of negative factors the product is negative

Chapter 3:

Dividing Integers

Partitive Division is when you use groups of to get to your quotient.

6/2=3

(-6)/(-2)= +3

(-6)/2= (-3)

Multiplicative Inverse is when you use multiplication to figure out your quotient.

6/(-2)=

(-2)x(-3)=6

(-3)x(-2)=6

Means 6/(-2)=(-3)

Sign Rules

In a divison question with an even amount or no negative signs the quotient will be positive.

example: 6/2=3

(-6)/(-2)=3

In a divison question with an odd number of negative signs the quotient will be negative.

example (-6)/2=3

6/(-2)= (-3)

Chapter 4

Order of Operations with Intergers

(+5)x(-3) + (-6)/(+3)=

Scince there are no square brackets or exponents we should start with division and multiplication going from left to right.

[(+5) x (-3)] +[(-6)/(+3)]=

(-15)=(-2)=

After your done with division and multiplication you should do the addition

(-15)+(-2)=(-17)

Katerina's Great Big Book Of Integers

Chapter One :
Here is what we did in class. First, we discussed on how we could solve a integer problem.


We can ...
use a number line :















Or integer Chips :

We also discussed Zero Pairs.

Zero Pairs : A pair of numbers that has a sum of zero. Something really easy to remember is .....

" When subtracting something that isn't there use a zero pair. "

Questions we did in Class :

Question one :

Question Two :

Chapter Two :

(+2) x (+3) = +6

(+2) x (-3) = -6

(-2) x (+3) = -6


(-2) x (-3) = +6






Chapter Three :


Partitive division : is groups of.
Queston one :

6/2 = 3

How many groups of (+2) are in (+6)







(-6)/(-2)= -3






Quotative division : spliting something between a number of groups.


(-6)/2= -3







Chapter Four :




Order of operations:



(+5)x(-3)+(-6)/(+3)=






I rewrote it and got



(+6)x(-3)+[(-6)/(+3)]=






My answer (-18)

How I solved it :




First :

(-6)-(+3) = -3

- - - - - -

+ + +






Then three times there is a zero pair : then you are left with -3. Then I solve the second part of my question.




(+5)x(-3) = (-15)



(-3) + (-15) = (-18)

Then I add both answers together and I got (-18)



THE END !!