Our project was on "Poverty In Winnipeg"
My First Draft:
The changes I made to make my project better was that I made my slides slower. I noticed myself that I couldn't read the slides. Another thing I changed was the spelling mistakes. I also corrected my grammar. the student comments helped me a lot because of the things I didn't see like my spelling mistakes.
My Final Draft:
We found our expert by going to Winnipeg Harvest. Three important fact the Kate Reynolds told us was " There are over 300 agencies across Manitoba " " Half of the children who come for emergency services are under the age 18 " and " Poverty rates in Winnipeg get higher each year. " I learned that By raising money and donating it to Winnipeg Harvest, we can halp FIVE people. I also learned that some people can't get everything they need from Winnipeg harvest because they have to give an even amount of food/other things to everyone who goes there. I think that our greatest success from the two minutes video was learning and understand what being in poverty is like. Poverty honestly doesn't feel great. One skill I will take with me next year is how much we searched for information. We ended up having to leave out quite a bit of information. What really frustrated me the most was how much trouble it was to post it! I ended up posting it over and over again. I did get it on youtube, after my fifth try. the strategie I used to be successful was to ask lots of questions about posting a video up because I had a lot of trouble. I do believe that this two minutes project is important to grade eight students,but I also believe it's important to all people because you learn about what is really important in the world. From this project I learned stuff about poverty, but from watching other videos I learned stuff about animal creulty too. I also learned about team work. Team work can be hard when doing a project like this but, there are many ways to get to success! In the future, I will make a difference by donating food to Winnipeg harvest more often and by raising money.
Video made by: Katerina, Jennily, and Krizna.
This is a place for the community of learners in Room 8-73 to learn and enjoy math. It is an extension of the classroom making it accessible 24 hours a day, 7 days a week.
Showing posts with label Katerina873. Show all posts
Showing posts with label Katerina873. Show all posts
Wednesday, June 15, 2011
Katerina's Two Minutes Reflection
Sunday, May 8, 2011
Katerina's Algebra Post
RED : +
BLUE : -
**REMEMBER**
Isolate The VARIABLE!
Cancel The constant with A ZERO PAIR
Balance
Verify
One step :
3+n = 6
-3+3+n=6-3
n = 3
3+n=6
3+3=6
6=6
Algebra Tiles:

Question Two:
m - 9 = -13
+ 9 + 9
m = -4
m - 9 = -13
(-4)-9 -13
-13 = -13

Question Three:
2x =6
/2 /2
1x =3
x =3
2x=6
2(3)=6
6=6

Question Four:
x/2 = 3
(2)x/2=3(2)
x=6
x/2=3
6/2=3
3=3

**REMEMBER**
Isolate
Cancel Constant
Simify Variable
Balance
Verify
Two Step:
Question One:
2x + 1 = 5
2x +1-1 =5-1
2x = 4
2 2
x = 2
2x+1=5
2(2)+1=5
5=5
BLUE : -
**REMEMBER**
Isolate The VARIABLE!
Cancel The constant with A ZERO PAIR
Balance
Verify
One step :
3+n = 6
-3+3+n=6-3
n = 3
3+n=6
3+3=6
6=6
Algebra Tiles:
Question Two:
m - 9 = -13
+ 9 + 9
m = -4
m - 9 = -13
(-4)-9 -13
-13 = -13

Question Three:
2x =6
/2 /2
1x =3
x =3
2x=6
2(3)=6
6=6

Question Four:
x/2 = 3
(2)x/2=3(2)
x=6
x/2=3
6/2=3
3=3

**REMEMBER**
Isolate
Cancel Constant
Simify Variable
Balance
Verify
Two Step:
Question One:
2x + 1 = 5
2x +1-1 =5-1
2x = 4
2 2
x = 2
2x+1=5
2(2)+1=5
5=5
Monday, March 21, 2011
Katerina'sTerm Two Reflection
Listen!'>Term Two Reflection
Sorry I didn't know how to add the thing on like everyone else.
Hello, I am Katerina from room 8-73!
Term two:
I did very well in volume and surface area. I really enjoyed working on it. One thing I really struggled on is the percent unit. In percent I learned how to find the tax of an object. Next term I hope to do better and finsh all of my homework! Also, i hope to do better in term three. The difference between surface area and volume is that the volume is the volume of and surface area is the surface of the object. then you add it up and to get Total Surface Area!
Thanks.
Sorry I didn't know how to add the thing on like everyone else.
Hello, I am Katerina from room 8-73!
Term two:
I did very well in volume and surface area. I really enjoyed working on it. One thing I really struggled on is the percent unit. In percent I learned how to find the tax of an object. Next term I hope to do better and finsh all of my homework! Also, i hope to do better in term three. The difference between surface area and volume is that the volume is the volume of and surface area is the surface of the object. then you add it up and to get Total Surface Area!
Thanks.
Monday, March 14, 2011
Katerina's Great Big Book Of Integers
Chapter One :
Here is what we did in class. First, we discussed on how we could solve a integer problem.
We can ...
use a number line :

Or integer Chips :





(-2) x (+3) = -6

(-2) x (-3) = +6

Chapter Three :
Partitive division : is groups of.
Queston one :
6/2 = 3
How many groups of (+2) are in (+6)

(-6)/(-2)= -3

Quotative division : spliting something between a number of groups.
(-6)/2= -3

Chapter Four :
Order of operations:
(+5)x(-3)+(-6)/(+3)=
I rewrote it and got
(+6)x(-3)+[(-6)/(+3)]=
My answer (-18)
How I solved it :
First :
(-6)-(+3) = -3
- - - - - -
+ + +
Then three times there is a zero pair : then you are left with -3. Then I solve the second part of my question.
(+5)x(-3) = (-15)

(-3) + (-15) = (-18)
Then I add both answers together and I got (-18)
THE END !!
Here is what we did in class. First, we discussed on how we could solve a integer problem.
We can ...
use a number line :

Or integer Chips :

We also discussed Zero Pairs.
Zero Pairs : A pair of numbers that has a sum of zero. Something really easy to remember is .....
Questions we did in Class :
Question one :

Question Two :

Chapter Two :
(+2) x (+3) = +6

(+2) x (-3) = -6

(-2) x (+3) = -6

(-2) x (-3) = +6

Chapter Three :
Partitive division : is groups of.
Queston one :
6/2 = 3
How many groups of (+2) are in (+6)

(-6)/(-2)= -3

Quotative division : spliting something between a number of groups.
(-6)/2= -3

Chapter Four :
Order of operations:
(+5)x(-3)+(-6)/(+3)=
I rewrote it and got
(+6)x(-3)+[(-6)/(+3)]=
My answer (-18)
How I solved it :
First :
(-6)-(+3) = -3
- - - - - -
+ + +
Then three times there is a zero pair : then you are left with -3. Then I solve the second part of my question.
(+5)x(-3) = (-15)

(-3) + (-15) = (-18)
Then I add both answers together and I got (-18)
THE END !!
Labels:
"dividing integers",
"multiplying integers",
"Order of Operations With Integers",
integers,
Katerina873
Monday, February 7, 2011
Katerina's Scribe Post
I have done questions 2,4,6, and 8.
2.) Explain why you need to find the circumference of a circle to find the surface area of a cylinder?
This is what I think.
You need to find the circumference of a circle to find the surface area of a cylinder because in order to find the surface area, in the end you have to add it up to get your TOTAL SURFACE AREA.
4.) Estimate the surface area of each cylinder. Then, calculate each surface area to the nearest cenimetre.
This is what I did.
On the first cylinder it is d = 7cm and the height is 30cm.
*remember to write down your formula because you can lose a half mark on a test!*
(pi x r 2) + (pi x d x h) = Total surface area
A.) d/2 = r
7/2 = 3.5cm2
(3.14 x 3.5 x 3.5)+(3.14 x 7 x 30) = 697.86cm2
38.46cm2 + 659.4cm2 = 697.86cm2
Total Surface Area = 697.86cm2
(pi x r 2)+(pi x d x h) = Total surface area
B.)(3.14 x 10 x 10)+(3.14 x 20 x 22) = 1695.6cm2
314cm2 + 1381.6cm2 = 1695.6cm2
Total Surface Area = 1695.6cm2
6.) Use the formula, (pi x r 2)+(pi x d x h) to calculate the surface area of each object. Give your answer to the nearest hundredth of a square unit.
A.)(3.14 x 1.25 x 1.25)+(3.14 x 2.5 x 10)
4.90cm2 + 78.5cm2
Total Surface Area = 83.4cm2
B.) d/2= r
5/2=2.5
(3.14 x 2.5 x 2.5)+(3.14 x 5 x 7)
19.62cm2 + 109.9cm2
Total Surface Area = 129.52cm2
8.) Anu wants to re-cover the cylindrical stool in his bedroom. how much material will he need if there is no overlap and he does not cover the bottom of the stool.
This is what I did.
Formula = (pi x r x r)+(pi x d x h)
d/2= r
42/2 = 21
(3.14 x 21 x 21)+(3.14 x 42 x 32)
1384.71cm2 + 4220.16cm2 - 21 =
Total Surface Area = 5583.87cm2
Here is a link on cylinder and a little bit about Volume!
Here is a link to a helpful video.
Cylinder Problems from 7.3

A.) Volume = (pi x r x r) x h
d/2 = r 8/2 = r r = 4 cm
(3.14 x 4 x 4) = 50.24 cm^2
50.24 cm^2 x 12 cm = 602.88 cm^3
Volume = 602.88 cm^3
B.) Volume = ( pi x r x r) x h
d/2 = r 2/2 = r r = 1 cm
(3.14 x 1 x 1) = 3.14 cm^2
3.14 cm^2 x 7 = 21.98 cm^3
Volume = 21.98 cm^3
C.) Volume = ( pi x r x r ) x h
d/2 = r 12/2 = r r = 6 cm
( 3.14 x 6 x 6 ) = 113.04 cm^2
113.04 cm^2 x 37.5 = 4239 cm^3
Volume = 4239 cm^3
D.) Volume = ( pi x r x r ) x h
d/2 = r 4.5/2 = r r = 2.25 cm
( 3.14 x 2.25 x 2.25 ) = 15.89625 cm^2
15.89625 cm^2 x 19.5 = 309.976875 cm^3
Volume = 309.976875 cm^3
Cylinder problems from 7.4

A.) Yes, he does have enough small prisms.
B.) The volume of the new prism is 22.4672^3
Here is what I did.
V= B x h / 2 x h
V = 5.6 x 6.8 / 2 = 19.04 x 1.18 = 22.4672^3
2.) Explain why you need to find the circumference of a circle to find the surface area of a cylinder?
This is what I think.
You need to find the circumference of a circle to find the surface area of a cylinder because in order to find the surface area, in the end you have to add it up to get your TOTAL SURFACE AREA.
4.) Estimate the surface area of each cylinder. Then, calculate each surface area to the nearest cenimetre.
This is what I did.
On the first cylinder it is d = 7cm and the height is 30cm.
*remember to write down your formula because you can lose a half mark on a test!*
(pi x r 2) + (pi x d x h) = Total surface area
A.) d/2 = r
7/2 = 3.5cm2
(3.14 x 3.5 x 3.5)+(3.14 x 7 x 30) = 697.86cm2
38.46cm2 + 659.4cm2 = 697.86cm2
Total Surface Area = 697.86cm2
(pi x r 2)+(pi x d x h) = Total surface area
B.)(3.14 x 10 x 10)+(3.14 x 20 x 22) = 1695.6cm2
314cm2 + 1381.6cm2 = 1695.6cm2
Total Surface Area = 1695.6cm2
6.) Use the formula, (pi x r 2)+(pi x d x h) to calculate the surface area of each object. Give your answer to the nearest hundredth of a square unit.
A.)(3.14 x 1.25 x 1.25)+(3.14 x 2.5 x 10)
4.90cm2 + 78.5cm2
Total Surface Area = 83.4cm2
B.) d/2= r
5/2=2.5
(3.14 x 2.5 x 2.5)+(3.14 x 5 x 7)
19.62cm2 + 109.9cm2
Total Surface Area = 129.52cm2
8.) Anu wants to re-cover the cylindrical stool in his bedroom. how much material will he need if there is no overlap and he does not cover the bottom of the stool.
This is what I did.
Formula = (pi x r x r)+(pi x d x h)
d/2= r
42/2 = 21
(3.14 x 21 x 21)+(3.14 x 42 x 32)
1384.71cm2 + 4220.16cm2 - 21 =
Total Surface Area = 5583.87cm2
Here is a link on cylinder and a little bit about Volume!
Here is a link to a helpful video.
Cylinder Problems from 7.3

A.) Volume = (pi x r x r) x h
d/2 = r 8/2 = r r = 4 cm
(3.14 x 4 x 4) = 50.24 cm^2
50.24 cm^2 x 12 cm = 602.88 cm^3
Volume = 602.88 cm^3
B.) Volume = ( pi x r x r) x h
d/2 = r 2/2 = r r = 1 cm
(3.14 x 1 x 1) = 3.14 cm^2
3.14 cm^2 x 7 = 21.98 cm^3
Volume = 21.98 cm^3
C.) Volume = ( pi x r x r ) x h
d/2 = r 12/2 = r r = 6 cm
( 3.14 x 6 x 6 ) = 113.04 cm^2
113.04 cm^2 x 37.5 = 4239 cm^3
Volume = 4239 cm^3
D.) Volume = ( pi x r x r ) x h
d/2 = r 4.5/2 = r r = 2.25 cm
( 3.14 x 2.25 x 2.25 ) = 15.89625 cm^2
15.89625 cm^2 x 19.5 = 309.976875 cm^3
Volume = 309.976875 cm^3
Cylinder problems from 7.4

A.) Yes, he does have enough small prisms.
B.) The volume of the new prism is 22.4672^3
Here is what I did.
V= B x h / 2 x h
V = 5.6 x 6.8 / 2 = 19.04 x 1.18 = 22.4672^3
Labels:
"cylinder volume",
"volume problems",
Katerina873,
scribe post
Monday, January 17, 2011
Final Percent Post
What is a Percent??
- A percent is a number out of one hundred.
4.1 Representing Percents
- To represent a percent you can use a hundred grid
- If all of the squares are coloured in then that is 100%
- To represent a fractional percent in between 0 and 1% you colour in part of one little square
4.2 Fractions, Decimals, and Percents
- Fractions decimals and percents can be used to represent numbers
- Percents can be shown as a......
- Fractions or a
- Decimals
- (example) 250% = 250 /100
4.3 Percent of a Number
- You can use mental math stratagies such as doubling, halving, doubling or dividing by ten to find the percent of some numbers.
4.4 Combining Percents
- To solve problems like this you can do that by adding
- a good example is 5% + 7% = 12%
- Percents can be used to determine the amounts that result from consecutive percents increasing or decreasing
Here is a website about percents.
Here is the video I created.
Hope it helps! (:
Tuesday, December 21, 2010
Katerina's Percent Scribe Post
I chose questions 3,4,8
3. Use mental math to determine each of the following.
a) 300% of 2000
=6000
b) 1 1/4% of 60
=0.72
c) 0.1% of 40
=0.04
4. Use mental math to find the following.
a) 20% of 60
=12
b) 250% of 400
=1000
c) 10 1/2% of 100
=10.5
8. The original price of a jacket was $84.00. A store manager marked the price down by 25 1/2 %. By how much was the price reduced.
The price reduced by $21.42.
3. Use mental math to determine each of the following.
a) 300% of 2000
=6000
b) 1 1/4% of 60
=0.72
c) 0.1% of 40
=0.04
4. Use mental math to find the following.
a) 20% of 60
=12
b) 250% of 400
=1000
c) 10 1/2% of 100
=10.5
8. The original price of a jacket was $84.00. A store manager marked the price down by 25 1/2 %. By how much was the price reduced.
The price reduced by $21.42.
Sunday, December 19, 2010
Katerina's Pay It Foward
Pay it forward is when someone does something nice to someone they know or not and not expecting anything in return. All that happens is that when you do something nice and helpful that person can also spread cheer at any time of the year. In the end almost everyone will be either doing something nice for someone or someone will be doing good deeds for you.
My pay it forward or act of kindness is going to buy toys for kids who need it. I choose this because I think that everyone in the world should have Christmas. not just you are me, everyone. I helped kids that are poor and need a Christmas present. Me and Jennily bought toys for kids who needed them, and now because me and Jennily bought toys now a kid who wants a gift will now have one. I did my act of kindness on Sunday,December 12, 2010.
Jennily paid for half of the toys and donated it but sadly isn't in the photo.
Me and jennily's act of kindness went bad at first but in the end it got brighter. Me and Jennily at first were going to donate to the children's hospital but sadly they were closed on weekends. "Bummer". But after that we went to the Christmas Cheer Board. After I took a picture with a very kind man he gave me a note that said " It's people like you who help fill the sack, To bring Christmas cheer to those who lack.. You're now officially Santa's ELF! You've put others first,before yourself. Please accept this sincere "Thanks" ..... For donations given.... and showing that you care, 'Cause it's only with your help that we can " LOVE and SHARE " and " Christmas should happen for EVERYONE ". I felt good that I have helped some in need because everyone in the whole wide world should be able to have Christmas. The person reacted by saying thanks and of course asking what pay it forward means. Yes, I did ask them to pay it forward. There reaction was " what is pay it forward?". I finally told them what pay it forward is and they were amazed by what this school's assignment was, I told them that its not a assignment, it is something that everyone in the world should do.
I think that the idea of pay it forward is important because not everyone in the world are like you and me. Some people don't even have house or food. So in the end I think it is so important for people to have food, and even toys for little kids. I hope my act of kindness bring joy for the child or children who get it.
Don't forget to PAY IT FORWARD !
HAPPY HOLIDAYS!
Sunday, November 7, 2010
Katerina's Scribe post
Questions 1 , 6 , 13 and 20.
1.) Describe using words and symbols the relationship among the areas of the three squares shown.The relationship is the S2 + V2 = T2 is the same as A2 + B2 = C2.
6.) Write an addition statement using the areas of these three squares.
The addition statement I got was 25 + 144 = 169
25 = 5x5 = 52
144 = 12x12 = 12 2
169 = 13x13 = 132
5 cm
12 cm
13 cm
6.) Describe using words and symbols the relationship between the side lengths of the squares.
The relationship between them is that the sum of the areas smaller squares equal the areas of the largest square.
13.) A small triangular flower bed has a square steeping stone on each side, is the flower bed the shape of a right triangle ? Explain.
No it isn't because the sum of the smaller squares isn't equal to the area of the larger square.
20.) A right triangle has sides of 13 cm, 4 cm, and 5 cm. Attached to each side is a semi circle instead of a square. Describe the relationship between the areas and the semi circles.
The sum of the area of the two smaller semi circles is equal to the area of the squares by the hypotenuse.
Here is a Pythagoras game that you can try.
Here is a site to help you understand this.
If I made any mistakes please let me know!
Sunday, October 17, 2010
Sesame Street Video
Group: Katerina, Emily, Marysa
Ratios: Compares two quantities measured in the same units.
Cats:Dogs
48:45
Rates:Compares two quantities measured in different units.
72 beats per minute.
Proportional Reasoning:A relationship that says that two ratios or two rates are equal.

Here is a link to the sesame street video, Pick a card Any card.
This Video is about Grover doing a card trick for his friend Chris.
Here is my groups video... Pick a Rate any Rate!
Saturday, October 2, 2010
Katerina's Math Profile
Hey! My name is Katerina. I am a grade eight math student. If someone was to ask me if i like math i would say kind of. Why you ask? because I ain't the strongest in math. One thing that i did in math class that was super fun was in grade two and we were added and subtracting with chocolate chips and then if we got the right answer we would go to the next level, once we got to the end we were able to eat the chocolate chips.
In grade seven my best unit was Integers. I thought that adding the integers using a number line was very easy until we did it in class. Once I got practice it was a piece of yummy cake! The hardest thing for me in grade seven was algebraic equations. One thing I worked on to help me with algebraic equations was to practice in the grade seven homework book.
One thing I should work on to become a better learner is to take lots of notes and study a little more then I do now. One other thing i would like to work on is to finish homework on time and not late. I would like to learn more about is algebraic equations because it would help me out and maybe even other students in the school.
One of my best posts from last year was my " Solving one step algebra equations ". The comments I got were wonderful and very helpful for the next time I post something. Blogging helped me as a learner because of all the comments I got. Some were great and some were very helpful! Also all the posts that other classmates posted really helped me to. This year on the computer I want to be able to post more things to help me and my classmates with math because I know I am not the only one who is struggling.
In grade seven my best unit was Integers. I thought that adding the integers using a number line was very easy until we did it in class. Once I got practice it was a piece of yummy cake! The hardest thing for me in grade seven was algebraic equations. One thing I worked on to help me with algebraic equations was to practice in the grade seven homework book.
One thing I should work on to become a better learner is to take lots of notes and study a little more then I do now. One other thing i would like to work on is to finish homework on time and not late. I would like to learn more about is algebraic equations because it would help me out and maybe even other students in the school.
One of my best posts from last year was my " Solving one step algebra equations ". The comments I got were wonderful and very helpful for the next time I post something. Blogging helped me as a learner because of all the comments I got. Some were great and some were very helpful! Also all the posts that other classmates posted really helped me to. This year on the computer I want to be able to post more things to help me and my classmates with math because I know I am not the only one who is struggling.
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