Volume Post

This is a Cylinder problem.

Pi.r.r.h
πx5x5=79cm^3
79x23=V
1,817=V

This is my triangular prism problem.

a) Yes, he has enough, he only needs 16 triangles
b) 5.6x6.8/2x1.18= 22.46^2

Surface Area and Volume Post

Show You Know pg. 185

Calculate the surface area of this cylinder to the nearest tenth of a square centimetre.

Show You Know pg.185

Calculate the surface area of a cylindrical waste bucket without a lid that measures 28 cm high and 18 cm in diameter. Give your answer to the nearest square centimetre.


1. What are the similarities and differences between finding the surface area of a prism and finding the surface area of a cylinder?


3. a) Draw a net for this cylinder. b) Sketch a different net for this cylinder


5. Find the surface area of each object to the nearest tenth of a square unit.


Cylinder Problems and Volume Problems



d/2=r

8/2=r

4m=r

v= π.r.r.h

v=(3.14 x 4 x 4 ) x 10

v=50.25cm^2 x 10m

v=502.4 cm^3

502.4/2 = 251.2m^3

3 Cylinder Problems

____________________________________________________________________

Cylinder Volume and Volume Problems

r=d/2
r=0.26/2
r=0.13

a=Pi.r.r

a=3.14.0.13.0.13
a=0.053066cm^2

v=a of b x h
v=0.053066cm^2 x2.4m
v=0.127m3

0.127x35=
5cm^3( I rounded)















b x h/2
1.7x1.4=2.38m/2
=1.19m^2

area of the base x height
1.19m^2 x 1.18m=
1.4042m^3

14042m^3 x 16=
22.47cm^3

a)Yes he does.
b)22.47cm^3

Homework Book Pg 54-55

Choose 3 questions from pages 54 and 55

2. Calculate the surface area of each rectangular

prism to the nearest tenth of a centimeter squared.

length x width = a

S- 5 x 3.2 = 16 cm2

- 5 x 3.2 = 16 cm2

F- 11.5 x 5 = 57.5 cm2

- 11.5 x 5 = 57.5 cm2

T- 11.5 x 3.2 = 36.8 cm2

- 11.5 x 3.2 = 36.8 cm2

________________________________

Total Surface Area =220.6 cm2

length x width = a

F- 12 x 10.4 = 124.8 cm2

- 12 x 10.4 = 124.8 cm2

T- 10.4 x 4.5 = 46.8 cm2

- 10.4 x 4.5 = 46.8 cm2

S- 12 x 4.5 = 54 cm2

- 12 x 4.5 = 54 cm2

________________________

Total Surface Area = 451.2 cm2

3. Find the surface area of each triangular

prism to the nearest tenth of a meter squared.

a of a triangle = base x height divided by 2

a of rectangle = length x width

8 x 2.5 = 20 m2

10.6 x 2.5 = 26.5 m2

2.5 x 7m = 17.5 m2

7 x 8 = 56/2 = 28 m2

7 x 8 = 56/2 = 28 m2

___________________

Total Surface Area = 120 m2

a of a triangle = base x height divided by 2

a of rectangle = length x width

8 x 4.5 = 36 m2

8 x 4.5 = 36 m2

8 x 6 = 48 m2

6 x 3.35 = 20.1/2 = 10.5

6 x 3.35 = 20.1/2 = 10.5

_____________________

Total Surface Area = 140.1 m2

4. Ty is painting this storage bench for the deck.

How much area does he need to paint, to the nearest

hundredth of a square meter?

length x width = a

S- 0.38 x 0.5 = 0.19 m2

- 0.38 x 0.5 = 0.19 m2

F- 0.5 x 1.56 = 0.78 m2

- 0.5 x 1.56 = 0.78 m2

T- 1.56 x 0.38 = 0.5928 m2

- 1.56 x 0.38 = 0.5928 m2

________________________

= 3.1256 round up...

Total Surface Area = 3.13 m2

Cylinder Volume and Volume Problems




r = d / 2…………………….v = π.r.r.h asdfghjkl;………….502.4m3^ / 2 = 251.2m3^
r = 8 /2……………………..v = (3.14 x 4 x 4) x 10
r = 4m……………………….v = 50.24 m2^ x 10m
…….asdfghjkl;…………….v = 502.4 m3^





r = d / 2.......................v = π.r.r.h

r = 80 / 2……………….v = (3.14 x 40 x 40) x 45

r = 40cm……..….……..v = 5024 cm2^ x 45cm
……………………………..v = 226,080cm3^

226,080 / 80 = 2826cm2^

2826 / 3.14 = 900cm

√900 = 30cm

30 x 2 = 60cm -diameter

Mussie's Surface Area Scribe Post,volume

Here are the two rectangular prisms. Please find the Total Surface area using a net and by using the Top, Front and Side views of the prism.


The lengths of a rectangular prisms are 4 cm and 8 cm and 1 cm. What is its Total Surface Area?
A=LxW

8x4=32

1x4=4

1x8=8

A=32+4+8=44

A=44*2=88cm^2

The lengths of a rectangular prism are 2 cm and 6 cm and 2 cm. What is its Total Surface Area?

A=LxW

2x6=12

6x2=12

2x2=4

A=12+12+4=28

A=28x2=56cm^2

link

pi x r x r x h

3.14 x 5 x 5
78.5x23cm
v=1805.5cm^3



















Yes he has enough
1.18x5.61/2=3304
3304m^2x6.8=22467.2
v=22467.2