Ana Lopena's Algebra Post

Variable- a letter that represents a number in an equation or expression

ex. n,x,p,z

Constant- the integer in algebra

ex.

Equation- only one possible answer. includes an equal sign - =

ex. 2x=6

Expression- a pattern many possible answers

ex. 2x

Algebra tiles

How to solve one step algebra

1. Isolate the variable

2. Cancel using the opposite

-make a zero pair with the constant

3. Balance the equation

4. Verify

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How to solve two-step equations

1. Isolate

2. Cancel constant

3. Balance

4. Simplify the variable

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Term 2 Reflection

Ana Lopena's Great Big Book Of Intergers

Chapter 1

Grade 7 Integer Review

Integers can be represented with number lines or integer chips.

negative- blue

positive - red

zero pairs- a pair of negative and positive numbers whose sum is 0.

ex. (-8) + (+8) = 0, (-20) + (+20) = 0

Here is a song to help you remember when to use a zero pair- *When subtracting something that isn't there use a zero pair!*

This is how we wrote integers in grade seven

Here are some questions that we did.

Chapter 2

Multiplying Integers

Here we learned how to multiply integers, here are some questions that we did.

For questions needing a zero pair you can find out how many zero pairs you need by multiplying the two factors in the question without their negative or positive signs.

ex. (-2) x (+3) - 2 x 3 = 6

6 zero pairs

Chapter 3

Dividing Integers

Partitive Division or Groups of

If you know the number of groups, but you don't know the number in each group then that is partitive division.

Quotative Division

If you know the number that is in each group, but you don't know the number of groups then that is quotative division.

You can also find the answer to a division question using multiplicated inverse-

In a division question with an even amount or no (-) signs the quotient will be positive.

In a division question with an odd number of negative signs the quotient will be negative.

Chapter 4

Order of Operations with Integers

(+5) x (-3) + (-6) ÷ (+3)=

To answer this question you will need to follow the rules of B.E.D.M.A.S.

Brackets, Exponents, Division, Multiplication, Adding, Subtracting

First add square brackets around the expressions with a x or ÷ to help remind you to answer them first. The square brackets means that you should answer the question in them before you do anything else.

Now answer, and write it in a new line on your paper.

Now all that you have to do is answer it.

Homework Book Pg 54-55

Choose 3 questions from pages 54 and 55

2. Calculate the surface area of each rectangular

prism to the nearest tenth of a centimeter squared.

length x width = a

S- 5 x 3.2 = 16 cm2

- 5 x 3.2 = 16 cm2

F- 11.5 x 5 = 57.5 cm2

- 11.5 x 5 = 57.5 cm2

T- 11.5 x 3.2 = 36.8 cm2

- 11.5 x 3.2 = 36.8 cm2

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Total Surface Area =220.6 cm2

length x width = a

F- 12 x 10.4 = 124.8 cm2

- 12 x 10.4 = 124.8 cm2

T- 10.4 x 4.5 = 46.8 cm2

- 10.4 x 4.5 = 46.8 cm2

S- 12 x 4.5 = 54 cm2

- 12 x 4.5 = 54 cm2

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Total Surface Area = 451.2 cm2

3. Find the surface area of each triangular

prism to the nearest tenth of a meter squared.

a of a triangle = base x height divided by 2

a of rectangle = length x width

8 x 2.5 = 20 m2

10.6 x 2.5 = 26.5 m2

2.5 x 7m = 17.5 m2

7 x 8 = 56/2 = 28 m2

7 x 8 = 56/2 = 28 m2

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Total Surface Area = 120 m2

a of a triangle = base x height divided by 2

a of rectangle = length x width

8 x 4.5 = 36 m2

8 x 4.5 = 36 m2

8 x 6 = 48 m2

6 x 3.35 = 20.1/2 = 10.5

6 x 3.35 = 20.1/2 = 10.5

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Total Surface Area = 140.1 m2

4. Ty is painting this storage bench for the deck.

How much area does he need to paint, to the nearest

hundredth of a square meter?

length x width = a

S- 0.38 x 0.5 = 0.19 m2

- 0.38 x 0.5 = 0.19 m2

F- 0.5 x 1.56 = 0.78 m2

- 0.5 x 1.56 = 0.78 m2

T- 1.56 x 0.38 = 0.5928 m2

- 1.56 x 0.38 = 0.5928 m2

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= 3.1256 round up...

Total Surface Area = 3.13 m2

Cylinder Volume and Volume Problems




r = d / 2…………………….v = π.r.r.h asdfghjkl;………….502.4m3^ / 2 = 251.2m3^
r = 8 /2……………………..v = (3.14 x 4 x 4) x 10
r = 4m……………………….v = 50.24 m2^ x 10m
…….asdfghjkl;…………….v = 502.4 m3^





r = d / 2.......................v = π.r.r.h

r = 80 / 2……………….v = (3.14 x 40 x 40) x 45

r = 40cm……..….……..v = 5024 cm2^ x 45cm
……………………………..v = 226,080cm3^

226,080 / 80 = 2826cm2^

2826 / 3.14 = 900cm

√900 = 30cm

30 x 2 = 60cm -diameter

Final Percent Post

1) Percents are out of 100. It is also another name for hundredths. Percents can be represented in fractions, decimals, and grids. In this unit we learned how to convert percents into decimals and fractions. We learned how to combine percents, and how to find a certain percent of a number.

4.1 Representing Percents

You can represent percents using hundred grids.

eg. 50%

4.2 Fractions, Decimals, and Percents

You can convert fractions and decimals into percents.

eg. 50%

4.3 Percent of a number

You can find the percent of a number by using mental math strategies.

ex. halving, doubling or dividing by 10

You can also find the percent of a number by converting the percent to a decimal and multiplying it by the number.

ex. 10% of 100

10 divided by 100= 0.1

0.1 x 100 = 10

4.4 Combining Percents

You can combine percents by adding to solve problems.

ex. 5% + 7% = 12%

2) Here is the video I made on percents

3) Here is a link to my percent scribe post ---->*click here*

4) Here is a link that explains more about percents. ---->*click here*

Ana Lopena's Percent Scribe Post

Choose 3 questions on pages 142 and 143.

4. Use mental math to find the following.

a) 20% of 60

b) 250% of 400

c) 10 1/2% of 100

5. Determine the percent of each number.

Give your answer to the nearest

hundredth.

a) 2/5% of 325

b) 15 1/4% of 950

c) 175% of $125.50

* another way to find the percent of a number is dividing the percent by 100 then multiply the answer with the number*

7. Two hundred tickets are being sold for a

school draw.

a) What is your chance of winning with

one ticket? Express your answer as

a percent.

b) How many tickets would you need

to purchase to have a 2.5% chance

of winning?