## Tuesday, November 9, 2010

### John's Pythagoras Scribe Post

Textbook Pages 98-100
#1 and 17

1.Explain how to estimate √28 to one decimal place without using a calculator.compare your answer with a classmate's

To estimate √28 you have to find the two closest perfect squares. 25 and 36 are just right because 28 is between these two perfect squares. There are two method or ways to find the estimate of the square root of 28
The first one is a number line

HOW?
What I did was put the perfect squares on both ends of the number line and then I decided which is closest 28 which was 25 and I took a guesstimate and I got 5.3

Other way is this
HOW!?
The method is the same as the number line except you write it different. You just find what number 28 is closest to which is 25 and take a guesstimate that would be logical not over 5.5 since its closest to 25.

18.
a) Evaluate √9.
b) Estimate the square root of your answer
in part a), to one decimal place.
c) Use a calculator to check your estimate.
hundredth.
d) How close is your estimate in part b)
to your calculation in part c)?

A)How to find the square root of 9? 9 is a perfect square so its easy, what I did was I looked for other perfect squares that are closest to 9 like 4 and 16 so 4 is 2x2 and 16 is 4x4 so 9 is 3x3 since its in the middle of 2 and 4
B)
C) The calculation is 1.73
D)My estimation in Part b was 0.2 larger than the actual calculation.

(HEY GUYS IF YOU FIND ANY MISTAKE, LEAVE A COMMENT AND PUT THE RIGHT ANSWER)