Understanding percents.
DEFINITIONS:
Percent- means it is out of a hundred or another name for hundredths
eg. 65% means 65 out of a 100 or 65/100 or o.65
Fractional percent- a percent that includes a portion of a percent.
eg. 1/2%, 0.42%, 7 3/8%, 125 3/4%, 4.5%
SHOW YOU KNOW:
page 125
A) 248% B)1/4% C)74 8/10%
Page 127
A)
B)
C)
This is a place for the community of learners in Room 8-73 to learn and enjoy math. It is an extension of the classroom making it accessible 24 hours a day, 7 days a week.
Tuesday, November 30, 2010
John Chua's scribe post
Thursday, November 18, 2010
Maya's Text Book Pages
Questions 3, 7, and 11. Pages 110 - 111
3. Walter walks across a rectangular field in a diagonal line. Maria walks around two sides of the field. They meet at the opposite corner.
7. What is the height of the wheelchair ramp? Give your answer to the nearest tenth of a centimetre.
The answer is 12.6
11. Johan has a 300cm ladder that he leans up against a wall. The safety sticker on the side of the ladder shows that the bottom must be placed between 70 cm and 110 cm away from the wall. What are the minimum distance and maximum distance up the wall that the ladder can reach? Give your answers to the nearest tenth of a centimetre.
The answer is 291.7 cm.
Here are two videos that may help you.
Here's a link to also help you.
3. Walter walks across a rectangular field in a diagonal line. Maria walks around two sides of the field. They meet at the opposite corner.
7. What is the height of the wheelchair ramp? Give your answer to the nearest tenth of a centimetre.
The answer is 12.6
11. Johan has a 300cm ladder that he leans up against a wall. The safety sticker on the side of the ladder shows that the bottom must be placed between 70 cm and 110 cm away from the wall. What are the minimum distance and maximum distance up the wall that the ladder can reach? Give your answers to the nearest tenth of a centimetre.
The answer is 291.7 cm.
Here are two videos that may help you.
Here's a link to also help you.
Louis' Homework book: 30 questions 2, 3, 4
Homework Book Pages 30 questions 2, 3, 4
b2=c2 - a2
a2=c2 - b2
a2 + b2 = c2
2) Use the relationship to determine the length of C in each triangle, to the the nearest whole number. Show your work.
A)
b2=c2 - a2
b2=262 - 242
b2=676 - 576
b2=100m2
square root 100 m2 and it becomes 10m
B)
a2=c2 - b2
a2=392 - 152
a2=1521 - 225
a2=1296 cm2
square root 1296 cm2 and it becomes 36cm
3) Determine the length of each hypotenuse. Show your work.
A)
a2 + b2 = c2
402 + 92 = c2
1600 + 81 = c2
1681 cm2 = c2
square root 1681 cm2 and it becomes 41cm
B)
a2 + b2 = c2
352 + 122 = c2
1225 + 144
1369m2 = c2
square root 1369 m2 and it becomes 37m
4) What is the length of each hypotenuse, to the nearest centimeter? Show your work.
A)
a2 + b2 = c2
82 + 92 = c2
64 + 81 = c2
145 = c2
square root 145 cm2 and it becomes 12.04cm
B)
a2 + b2 = c2
102 + 62 = c2
100 + 36 = c2
136 cm2 = c2
square root 136 cm2 and it becomes 11.66 cm
Jennily's Textbook Pages
Pg 108-110
Question 3,9,11
3. Walter walks across a rectangular field in a diagonal line. Maria walks around two sides of the field. They meet at the opposite corner. Express your answer to the nearest metre.
A) How far did Maria walk?
B) How far did Walter walk?
C) Who walked further? By how much?
A) Maria walked 420 Km.
B) Walter walked 323 Km.
C) Maria had walked more further by 97m.
9. A checkerboard is made of 64 small squares that each have a dimension of 3cm * 3cm. The 64 small squares are arranged in eight rows of eight.
A) What is the length of th diagonal of small square? Give your answer to the nearest tenth of a centimetre.
B) What is the total length of the diagonal of the board? Give your answer to the nearedt centimetre.
A) a square + b square = c square
3 square + 3 square = c square
9+9=18
c square = 18
c = 4.2 cm square
B) 32cm
11. Johan has a 300-cm ladder that he leans up against a wall. The safety sticker on the side of the ladder shows that the bottom must be placed between 70 cm and 110 cm away from the wall. What are the minimum distance and maximum distance up the wall that the ladder can reach? Give your answers to the nearest tenth of a centimetre.
The maximum is 291.7 cm, and the minimum is 279 cm.
Tuesday, November 16, 2010
Meldrick's Textbook Pages
The pages I had to do 7, 10, 13, and the deadly question 16.
Now, imagine that the triangle has been cut in half, from the top right corner to the bottom left corner, so that the diagonal is on a 'flat surface'. Using the height (5mm) and length (12mm), we can find the hypotenuse of the 'triangle' that was created when the rectangle was cut in half, using the Pythagorean theorem (height-a, length-b):
Hopefully, you found that helpful. Good night (it's 1:05 AM), and goodbye.
Number 7
What is the missing length of the leg for each triangle? Give your answer to the nearest tenth of a millimetre.
a)
a²+b²=c²
a²+5²=9²
a²+(5x5)=(9x9)
a²+25-25=81-25
a²=56 mm²
√a²=√56 mm²
√a²=√56 mm²
a=7.5 mm
b)
a²+b²=c²
a²+11²=15²
a²+(11x11)=(15x15)
a²+121-121=225-121
a²=104 mm²
√a²=√104
a=10.2 mm
Number 10
What is the minimum distance the player at third base has to throw to get the runner out at first base? Express your answer to the nearest tenth of a metre.
a²+b²=c²
27²+27²=c²
(27x27)+(27x27)=c²
729m²+729m²=c²
1458m²=c²
√1458=√c²
38.2m=c
The player must throw a distance of 38.2 metres.
Number 13
Determine the length of the base of the large triangle. Express your answer to the nearest tenth of a millimetre.
a²+b²=c²
8²+b²=10²
8²+b²=10²
(8x8)+b²=(10x10)
64-64+b²=100-64
64-64+b²=100-64
b²=36mm²
√b²=√36
b=6mm
b(2)=6(2)
Base=12cm
Number 16
The deadly number 16. Hopefully you won't need this guide, as it is for people who have been reduced to tears (not literally) by this question. But if you are one of these people, you are welcome to look at the answer.
What is the length of the red diagonal in the box? Express your answer to the nearest tenth of a millimetre.
Now, imagine that the triangle has been cut in half, from the top right corner to the bottom left corner, so that the diagonal is on a 'flat surface'. Using the height (5mm) and length (12mm), we can find the hypotenuse of the 'triangle' that was created when the rectangle was cut in half, using the Pythagorean theorem (height-a, length-b):
a²+b²=c²
5²+12²=c²
(5x5)+(12x12)=c²
25+144=c²
169cm²=c²
√169=√c²
13mm=c
After that, imagine turning the triangle so that you can see the red diagonal cutting a rectangle in half. You have already found the bottom of the rectangle (13mm), and you have the measurements for the right side of the rectangle, the width (7mm). Using the Pythagorean theorem, you can now find the red diagonal (width-a, bottom-b).
a²+b²=c²After that, imagine turning the triangle so that you can see the red diagonal cutting a rectangle in half. You have already found the bottom of the rectangle (13mm), and you have the measurements for the right side of the rectangle, the width (7mm). Using the Pythagorean theorem, you can now find the red diagonal (width-a, bottom-b).
7²+13²=c²
(7x7)+(13x13)=c²
49+169=c²
218cm²=c²
√218=√c²
14.8cm=c
Hopefully, you found that helpful. Good night (it's 1:05 AM), and goodbye.
Textbook Work
Textbook
I had to do numbers
5, 8, 11, and 14
5)
B)
The area of the square attached to the hypotenuse is 100
C)
The length of the hypotenuse is 10
Here's a link to help you guys!
I had to do numbers
5, 8, 11, and 14
5)
B)
The area of the square attached to the hypotenuse is 100
C)
The length of the hypotenuse is 10
14)
c²-b²=a²
5²-3²
25-9=a²
16m²=a²
√16m²= √a²
4m=a
**The √ are suppose to be square root signs.**
If you guys still don't understand what a hypotenuse is, maybe this video might help.
Here's a link to help you guys!
Mussie Mesgun Homework Book: Even Questions
2) Use the relationship to determine the length of C in each triangle, to the nearest whole number.show your work.
A) a²+c²=b²
24² cm 26² cm=c²
24² cm 26² cm=c²
-576 cm + 676 cm=c²
100 cm=c²
√100 cm=√c²
10cm=cB) a²+c²=b²
39² +15²=c²
1521 + 225 =c²
√1746=√c²
41.78 =c
42 = c
4)What is the length of each hypotenuse, to the nearest centimetre? show your work
A) a²+b ²=c²
8² cm + 9² cm=c²
64 cm +81cm=c²
√145cm =√c²
12.0cm=c
B) a²+b²=c²
6² cm +10² cm=c²
36 cm+100 cm=c²
√136cm²=√c²
11.6 = c
12 = c
12 = c
6) Find the height of triangle with a base of 4 cm and a hypotenuse of 11 cm. Round to the nearest tenth of a centimetre. show your work
a²+b²=c²
-4² cm +11² cm=b²
-16 cm +121cm=b²
√105cm=√b²
b=10.2
b = 10 cm
b = 10 cm
8) Ellie and Lucas are going to the skateboard park to try out the new ramp.
A) is the new ramp a right triangle? explain your thinking
Yes is a right triangle because it as a 90' angle
Using the Pythagorean Relationship, Homework Book
1. RED is the answer
The Pythagorean relationship can be used to determine the Length of the Hypotenuse of a right triangle when the lengths of the two Legs are known.
3. Question - Determine the length of each hypotenuse. Show your work.
a)
a squared + b squared = c squared
40cm squared + 9cm squared = c squared
(40x40) + (9x9) = c squared
1600cm + 81cm = c squared
The square root of 1681cm = c squared
41 cm squared = c squared
b)
a squared + b squared = c squared
12m squared + 35m squared = c squared
7. Question - A triangle is made up of two smaller congruent right triangles.
The Pythagorean relationship can be used to determine the Length of the Hypotenuse of a right triangle when the lengths of the two Legs are known.
3. Question - Determine the length of each hypotenuse. Show your work.
a)
a squared + b squared = c squared
40cm squared + 9cm squared = c squared
(40x40) + (9x9) = c squared
1600cm + 81cm = c squared
The square root of 1681cm = c squared
41 cm squared = c squared
b)
a squared + b squared = c squared
12m squared + 35m squared = c squared
(12x12) + (35x35) = c squared
144m squared + 1225m squared = c squared
The square root of 1369m squared = c squared
The square root of 1369m squared = c squared
37m squared = c squared
5. Question - Calculate the missing side length for each right triangle, to the nearest tenth of a centimetre. Show your work.
a)
a squared = c squared - b squared
a squared = 6 cm squared - 5 cm squared
a squared = (6x6) - (5x5)
a squared = 36cm squared - 25cm squared
The square root of 11 = a squared
a squared = 3.31cm squared
a squared = c squared - b squared
a squared = 6 cm squared - 5 cm squared
a squared = (6x6) - (5x5)
a squared = 36cm squared - 25cm squared
The square root of 11 = a squared
a squared = 3.31cm squared
b)
a squared = b squared - c squared
a squared = 7cm squared - 12cm squared
a squared = (7x7) - (12x12)
a squared = 49cm squared - 144cm squared
The square root of 95 = a squared
a squared = 9.74
a squared = 7cm squared - 12cm squared
a squared = (7x7) - (12x12)
a squared = 49cm squared - 144cm squared
The square root of 95 = a squared
a squared = 9.74
7. Question - A triangle is made up of two smaller congruent right triangles.
a)
a squared + b squared = c squared
4m squared + 2m squared = c squared
(4x4) + (2x2) = c squared
16+ 4 = c squared
The square root of 20 = c squared
4.5 = c squared
4.5 = c squared
Joshua's Pythagoras Scribe Post
9. Tina wants to construct a path along the diagonal of her yard. What length will the path be? Express your answer to the nearest tenth of a metre.
12. The hypotenuse of the triangle cuts the circle in half. What is the diameter of the circle? Express your answer to the nearest tenth of a centimetre.
15. The coordinate grid shown was drawn on centimetre grid paper. What is the line segment of AB? Express your answer to the nearest tenth of a centimetre.
Here is a video to help you:
Here is a link to help you.
If I made any mistakes, please tell me!
Monday, November 15, 2010
Hazel's Pythagorean Relationship Scribe Post
Key Ideas
The Pythagorean relationship can be used to determine the length of the hypotenuse of a right triangle when the lengths of two legs are known.
4.What is the length of each hypotenuse? Give your answer to the nearest tenth of a centimetre.
Here is a link to the textbook website.
Here is a link to a pythagoras website.
The Pythagorean relationship can be used to determine the length of the hypotenuse of a right triangle when the lengths of two legs are known.
The Pythagorean relationship can be used to determine the leg length of a right triangle when the lengths of the hypotenuse and the other leg are known.
1. Jack must determine the missing side of a triangle. He decides to draw it and then measure it,as shown. Do you agree with the method that Jack is using? Explain.
Answer: No, I don't agree with the method that Jack is using because it would take too much work. It would be easier if he just used the formula: a²+b²=c² then √c²=c (hypotenuse).
2. Kira calculated the missing side length of the right triangle.
Is Kira correct? If she is correct, explain how you know. If she is incorrect, explain the correct method.
Answer: Kira is incorrect. She should've used the formula b²=c²-a² or in this case, y²=x²-w².
3.Determine the length of the hypotenuse.
4.What is the length of each hypotenuse? Give your answer to the nearest tenth of a centimetre.
Here is a link to the textbook website.
Here is a link to a pythagoras website.
Friday, November 12, 2010
Maya's Text Book Scribe Post
# 10 and 16.
Page 98
10) Kai uses an entire can of paint on a square backdrop for the school play. The label on the can states that one can covers 27m² of wall surface. Estimate the backdrop side length, to one decimal place.
Answer:
5.2 is the estimation of 27m².
Page 100
16) A tub in a fitness centre will install a square hot tub in a 6 m × 6 m room. They want the tub to fill no more than 75% of the room’s area.
a) What is the maximum area of the hot tub?
Answer:
The maximum area of the hot tub is 27m²
The maximum area of the hot tub is 27m²
b) What dimensions, to a tenth of a metre, will the fitness centre order from the manufacturer? Explain.
Answer:
The dimensions should be 5.1 by 5.1 so the area does not exceed 75% of the space available.
The dimensions should be 5.1 by 5.1 so the area does not exceed 75% of the space available.
*Sorry if I didn't explain it well.
Here's a video to help you estimate square roots.
Wednesday, November 10, 2010
Samarab 8-73 Textbook Post
Pg. 98 and 100
6) What is an example of a whole number that has a square root between 9 and 10 ?
Answer: 90. 90 is a possible answer .
9) What are the possible whole numbers that has a square root between 4 and 5 ?
Answer : 17,18,19,20,21,22,23,24 . All theses are the possible answers .
6) What is an example of a whole number that has a square root between 9 and 10 ?
Answer: 90. 90 is a possible answer .
9) What are the possible whole numbers that has a square root between 4 and 5 ?
Answer : 17,18,19,20,21,22,23,24 . All theses are the possible answers .
Krizna's Textbook Post
Pg.100
Questions 7 and 8
7.Identify a whole number with a square root between 11 & 12
Answer: the square root of 11 is 111 and the square root of 12 is 144 the square root is 130.
8.Identify all possible whole numbers with a square root between 2 & 3.
Answer:the square root of 2 is 4 & and the square root of 3 is 9. The whole numbers are 5,6,7,8.
Questions 7 and 8
7.Identify a whole number with a square root between 11 & 12
Answer: the square root of 11 is 111 and the square root of 12 is 144 the square root is 130.
8.Identify all possible whole numbers with a square root between 2 & 3.
Answer:the square root of 2 is 4 & and the square root of 3 is 9. The whole numbers are 5,6,7,8.
mussie mesgun scribe post
Questions 15-16
15. order the following numbers from the least to greatest: 7, SQRT 46, 5.8, SQRT 27, 6.3
A) SQRT 27 < 5.8 < 6.3 < SQRT 46 < 7
16. Fitness centre will install a square hot tub in a 6 m x 6 m room. They want the tub to fill no more than 75% of the room's area.
A) What is the maximum area of the hot tub?
Area of a square = LxL
= 6 m x 6 m
= 36 m^2
Area of the hot tub :(75/100)(36) = 27 m^2
B) What dimensions, to a tenth of a meter, will the fitness centre order from the manufacturer?
Explain.
They want the hot tub to fill no more than 75% of the room.
so 75% of the room is : (75/100)(36)= 27 m^2
The dimensions are SQRT 27 = 5.196m
L = 5.1 m
L = 5.1 m
15. order the following numbers from the least to greatest: 7, SQRT 46, 5.8, SQRT 27, 6.3
A) SQRT 27 < 5.8 < 6.3 < SQRT 46 < 7
16. Fitness centre will install a square hot tub in a 6 m x 6 m room. They want the tub to fill no more than 75% of the room's area.
A) What is the maximum area of the hot tub?
Area of a square = LxL
= 6 m x 6 m
= 36 m^2
Area of the hot tub :(75/100)(36) = 27 m^2
B) What dimensions, to a tenth of a meter, will the fitness centre order from the manufacturer?
Explain.
They want the hot tub to fill no more than 75% of the room.
so 75% of the room is : (75/100)(36)= 27 m^2
The dimensions are SQRT 27 = 5.196m
L = 5.1 m
L = 5.1 m
Tuesday, November 9, 2010
Maya's Text Book Scribe Post
# 10 and 16.
Answer:
Here's a video to help you estimate square roots.
Page 98
10) Kai uses an entire can of paint on a square backdrop for the school play. The label on the can states that one can covers 27m² of wall surface. Estimate the backdrop side length, to one decimal place.
Answer:
5.2 is the estimation of 27m².
Page 100
16) A tub in a fitness centre will install a square hot tub in a 6m × 6m room. They want the tub to fill no more than 75% of the room’s area.
a) What is the maximum area of the hot tub?
Answer:
The maximum area of the hot tub is 27m²
The maximum area of the hot tub is 27m²
b) What dimensions, to a tenth of a metre, will the fitness centre order from the manufacturer? Explain.
Answer:
The dimensions should be 5.1 by 5.1 so the area does not exceed 75% of the space available.
The dimensions should be 5.1 by 5.1 so the area does not exceed 75% of the space available.
*Sorry if I didn't explain it well.
Here's a video to help you estimate square roots.
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